Asked by TP
How many moles of H2SO4 are present in 250 g of an aqueous solution that is 4.8 m (molal)? The density of the solution is1.58 g/mL.
Answers
Answered by
DrBob222
m = mols/kg solution.
So a 4.8 m soln is 4.8 mol/kg soln.
If you have 4.8 mols in 1 kg how much do you have in 250 g? Wouldn't that just be 4.8 mols x (250 g/1000 g) = ? = say 4.8/4 = 1.2 mols
So a 4.8 m soln is 4.8 mol/kg soln.
If you have 4.8 mols in 1 kg how much do you have in 250 g? Wouldn't that just be 4.8 mols x (250 g/1000 g) = ? = say 4.8/4 = 1.2 mols
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.