Asked by kay
The height of the Empire State building is 318.00 meters. A pebble is dropped from the top of the building, what is the stones velocity just before it strikes the ground?
Answers
Answered by
bobpursley
final KE=initial PE
1/2 m v^2=mgh
v=sqrt(2*9.8*318) ignoring air friction, which is significant.
1/2 m v^2=mgh
v=sqrt(2*9.8*318) ignoring air friction, which is significant.
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