Asked by AJ
Four distinct fair of dice are rolled. What is the probability that the sum of the resulting numbers is at least 23?
Answers
Answered by
Steve
24 is all sixes, so
P(24) = (1/6)^4
23 is 3 sixes and a five, so there are 4 ways of doing this, with
P(23) = 4*(1/6)^3 * (1/6)
...
P(24) = (1/6)^4
23 is 3 sixes and a five, so there are 4 ways of doing this, with
P(23) = 4*(1/6)^3 * (1/6)
...
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