24 is all sixes, so
P(24) = (1/6)^4
23 is 3 sixes and a five, so there are 4 ways of doing this, with
P(23) = 4*(1/6)^3 * (1/6)
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Four distinct fair of dice are rolled. What is the probability that the sum of the resulting numbers is at least 23?
1 answer