Asked by Alex
An iceberg has specific weight of 9000 N/m^3 in n ocean, which has a specific weight of 1000 N/m^3. Above the water surface, it was observed that a volume of 2800 m^3 of the iceberg protruded. Determine the volume of the iceberg below the free surface of the ocean.
Answers
Answered by
bobpursley
something is really wrong with your numbers.
Answered by
Henry
Given:
Di = 9000N/m^3 = Density of iceberg.
Dw = 10,000N/m^3? = Density of sea water.
Va = 2800m^3 = Vol. above surface.
Vb=(Di/Dw)*V=V-2800=Vol. below surface.
(9000/10000)*V = V-2800,
V = 28000 m^3 = Vol. of iceberg.
Vb = 28000-2800 = 25,200 M^2 Below surface.
Di = 9000N/m^3 = Density of iceberg.
Dw = 10,000N/m^3? = Density of sea water.
Va = 2800m^3 = Vol. above surface.
Vb=(Di/Dw)*V=V-2800=Vol. below surface.
(9000/10000)*V = V-2800,
V = 28000 m^3 = Vol. of iceberg.
Vb = 28000-2800 = 25,200 M^2 Below surface.
Answered by
Henry
Correction: Vb = 28,000-2800 = 25,200m^3 = Vol. below surface.
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