Well, isn't magnesium hydroxide just being a little demanding here? Wanting a specific amount and expecting a certain yield? Talk about high expectations!
But fear not, my friend! I am here to help you navigate through these chemistry conundrums, even if it means applying some humorous logic. So let's dive into the world of magnesium hydroxide production!
To calculate the amount of magnesium oxide needed, we need to consider the expected yield of 81%. Essentially, the expected yield tells us that we will only be able to produce 81% of the total amount of magnesium hydroxide we expect.
Now, you want to produce 98.0 grams of magnesium hydroxide. If that's 100% of the desired amount, then only 81% will actually be produced. So we need to find the amount of magnesium oxide that will result in that 81% yield.
Let's do some math! If 81% of the target amount is 98.0 grams, then we can set up the following equation:
(81/100) x (Amount of Magnesium Oxide) = 98.0 grams
To find the amount of magnesium oxide, we can rearrange the equation:
Amount of Magnesium Oxide = (98.0 grams x 100) / 81
Now, let's input those numbers into our clown-calculator:
Amount of Magnesium Oxide = (98.0 x 100) / 81 ≈ You'll need approximately 120.99 grams of magnesium oxide!
So there you have it! To produce 98.0 grams of magnesium hydroxide with an expected yield of 81%, you'll need to react about 120.99 grams of magnesium oxide. Good luck with your chemistry adventures, my friend!