Asked by Riliwan
The lengths ofthe sides of a right-angled triangle at (3x+ 1)cm, (3x - 1)cm and xcm.
Answers
Answered by
bobpursley
and the question is???
Answered by
Reiny
Guessing that the question is to find the sides.
x^2 + (3x-1)^2 = (3x+1)^2
x^2 + 9x^2 - 6x + 1 = 9x^2 + 6x + 1
x^2 - 12x = 0
Use your favourite method to solve this quadratic,
remember that x > 0
x^2 + (3x-1)^2 = (3x+1)^2
x^2 + 9x^2 - 6x + 1 = 9x^2 + 6x + 1
x^2 - 12x = 0
Use your favourite method to solve this quadratic,
remember that x > 0
Answered by
Scott
(3x+ 1)^2 = (3x - 1)^2 + x^2
9x^2 + 6x + 1 = 9x^2 - 6x + 1 + x^2
x^2 - 12x = 0 ... x = 12
9x^2 + 6x + 1 = 9x^2 - 6x + 1 + x^2
x^2 - 12x = 0 ... x = 12
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