Asked by Riliwan
Solve the following equations
4x – 3 = 3x + y = 2y + 5x – 12
4x – 3 = 3x + y = 2y + 5x – 12
Answers
Answered by
Reiny
from 4x – 3 = 3x + y
y = x - 3 **
plug ** into 3x + y = 2y + 5x – 12
3x + x-3 = 2(x-3) + 5x - 12
4x - 3 = 2x - 6 + 5x - 12
4x-3 = 7x - 18
-3x = -15
x = 5
then y = 5-3 = 2
y = x - 3 **
plug ** into 3x + y = 2y + 5x – 12
3x + x-3 = 2(x-3) + 5x - 12
4x - 3 = 2x - 6 + 5x - 12
4x-3 = 7x - 18
-3x = -15
x = 5
then y = 5-3 = 2
Answered by
Riliwan
Thanks
Answered by
Rukayat
Given a regular hexagon, calculate each interior angle of the hexagon
Answered by
Eke
Sum of interior angles in a polygon=(2n-4)x90°
Sum of interior angle in a hexagon=720°[6 sides]
(2n-4)x90°
(2(6)-4)x90°
12-4x90°
8x90°=720°÷6
=120°
Sum of interior angle in a hexagon=720°[6 sides]
(2n-4)x90°
(2(6)-4)x90°
12-4x90°
8x90°=720°÷6
=120°
Answered by
MYSTORY ANIMATED
120
Answered by
Bot
degrees.
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