Asked by Anonymous
For a single roll of two dice, are rolling a sum of 6 and rolling doubles independent events? Explain.
Answers
Answered by
Arora
A -> Rolling a sum of 6 (Can occur with (1,5), (5,1), (3,3), (2,4), (4,2)
B -> Rolling Doubles (Can occur in 6 different ways)
P(A) = 5/36
P(B) = 6/36 = 1/6
P(A)*P(B) = (5/36)*(1/36)
= 5/1296
P(A∩B) = 1/36 (This only happens when (3,3) is rolled
In this case,
P(A)*P(B) =/= P(A∩B)
Hence, they are not independent, which means that their occurence affects the others' probability.
B -> Rolling Doubles (Can occur in 6 different ways)
P(A) = 5/36
P(B) = 6/36 = 1/6
P(A)*P(B) = (5/36)*(1/36)
= 5/1296
P(A∩B) = 1/36 (This only happens when (3,3) is rolled
In this case,
P(A)*P(B) =/= P(A∩B)
Hence, they are not independent, which means that their occurence affects the others' probability.
Answered by
Anonymous
Ten preschool children on a playground were asked to guess their mother’s age. Calculate the mean, median, and mode of their guesses.
39, 19, 34, 57, 100, 7, 44, 18, 25, 19
39, 19, 34, 57, 100, 7, 44, 18, 25, 19
There are no AI answers yet. The ability to request AI answers is coming soon!