Asked by James
In 2010 the birthrate in a certain country increases from 11*(e^(0.04*t)) million births per year to 16*(e^(0.04*t)) million births per year, where t is the number of years since January 1, 2010.
Set up the integral and find the projected increase in population that would result due to the higher birth rate between January 1, 2010 and January 1, 2029.
(Express the limits as exact numbers.)
Set up the integral and find the projected increase in population that would result due to the higher birth rate between January 1, 2010 and January 1, 2029.
(Express the limits as exact numbers.)
Answers
Answered by
Steve
Not sure what difference it makes what the rate was before 2010, since we are told that the rate after 2010 is 16e^(.04t) per year after 2010.
So, now we have
dp/dt = 16e^(.04t)
so, during the next 19 years, the population grows by
∫[0,19] 16e^(.04t) dt
So, now we have
dp/dt = 16e^(.04t)
so, during the next 19 years, the population grows by
∫[0,19] 16e^(.04t) dt
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