Find A if the graph of the equation
Ax + 3y = 5 is parallel to the graph of 5x - 2y = 4
I tried to solve the problem, but I couldn't really get a good answer.
Thanks!
15 years ago
15 years ago
A/3 must equal 5/-2
so 15 = -2A
A = -15/2
15 years ago
You both really helped!
4 years ago
If a is a number then the equation is set
1 year ago
Well, I'll tell you something funny first. Did you hear about the mathematician who was afraid of negative numbers? He will stop at nothing to avoid them!
Now let's get to your question. The graphs of two linear equations are parallel if and only if their slopes are equal. So, we need to find the slopes of the two given equations.
To find the slope of the equation Ax + 3y = 5, we need to rewrite it in the slope-intercept form y = mx + b, where m is the slope. Let's isolate y:
Ax + 3y = 5
3y = -Ax + 5
y = (-A/3)x + 5/3
From this equation, we can see that the slope is -A/3.
Now, let's find the slope of the equation 5x - 2y = 4. Similarly, isolate y:
-2y = -5x + 4
y = (5/2)x - 2
From this equation, we can see that the slope is 5/2.
Now, to have the two equations be parallel, their slopes must be equal. So we can set up the equation:
-𝐴/3 = 5/2
Now we can solve for A:
-𝐴 = (5/2)(3)
-𝐴 = 15/2
𝐴 = -15/2
Therefore, A is equal to -15/2.
I hope that didn't turn into clown math! Let me know if you have any more questions!
11 months ago
To determine if the graphs of two equations are parallel, we can compare their slopes. The slope-intercept form of a linear equation is y = mx + b, where m is the slope.
So let's start by rearranging both equations into slope-intercept form:
Equation 1: Ax + 3y = 5
Rearranging, we get: 3y = -Ax + 5
Dividing every term by 3, we can rewrite the equation as: y = (-A/3)x + 5/3
The slope of this equation is -A/3.
Equation 2: 5x - 2y = 4
Rearranging, we get: -2y = -5x + 4
Dividing every term by -2 and rearranging, we can rewrite the equation as: y = (5/2)x - 2
The slope of this equation is 5/2.
Since we want the graphs to be parallel, the slopes must be equal. Therefore, we have the equation:
-A/3 = 5/2
To solve for A, cross-multiply and solve for A:
-2A = 15
Dividing both sides by -2, we get:
A = -15/2
So, if the value of A is -15/2, the graph of the equation Ax + 3y = 5 will be parallel to the graph of 5x - 2y = 4.
I hope this helps! Let me know if you have any other questions.