Asked by Gar
A .25 kg pool ball is moving at 5.0m/s E towards a second identical ball at rest. After the collision, the first ball is seen moving at 1.0 m/s E. what is the final velocity of the second ball?
Answers
Answered by
bobpursley
initial momentum=final momentum
.25*5+0=.25*1+.25V
solve for V
.25*5+0=.25*1+.25V
solve for V
Answered by
Henry
M1 = 0.25kg, V1 = 5.0 m/sw.
M2 = 0.25kg, V2 = 0.
V3 = 1.0 m/s = Velocity of M1 after the
collision.
V4 = ?.
Momentum before = Momentum after
M1*V1 + M2*V2 = M1*V3 + M2^V4.
0.25*5 + 0.25*0 = 0.25*1.0 * 0.25^V4,
V4 = ?
M2 = 0.25kg, V2 = 0.
V3 = 1.0 m/s = Velocity of M1 after the
collision.
V4 = ?.
Momentum before = Momentum after
M1*V1 + M2*V2 = M1*V3 + M2^V4.
0.25*5 + 0.25*0 = 0.25*1.0 * 0.25^V4,
V4 = ?
Answered by
aiden
4.0 m/s E
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