the spring provides the centripetal acceleration ... keeps the rock moving in a circle
f = k x = mv^2 / r ... v = 32 r
r = x + 1.5
k x r = m (32 r)^2 ... k x = 32^2 m (x + 1.5)
solve for x
A 18 kg rock is attached to a 52 N/m spring, you then start to swing the spring above your head in a horizontal circle at 32 radians/s. Calculate how far the spring will stretch during this motion assuming its relaxed length is 1.5meters. Ignore any effects of gravity
4 answers
why is it in the third line, when you moved 'r' over to the other side, you multipled? at
'k x = 32^2 m (x + 1.5)'. wouldn't it be
k x = 32^2 m / (x + 1.5)?
'k x = 32^2 m (x + 1.5)'. wouldn't it be
k x = 32^2 m / (x + 1.5)?
there was an r^2 on the right
... one of them cancelled with the r from the left
... one of them cancelled with the r from the left
thank you this helped alot
2 answers