Asked by Majiri
If the house on a particular stretch of road are all the old numbers starting at 11, how many houses are there if the total all the numbers is 551?
Answers
Answered by
Steve
assuming consecutive numbers, we have n houses if
n/2 (2*11+(n-1)*1) = 551
n = Hmmm, not an integer
How about a typo, and you meant "odd" numbers. Then we gate
n/2 (2*11+(n-1)*2) = 551
Then n=19
n/2 (2*11+(n-1)*1) = 551
n = Hmmm, not an integer
How about a typo, and you meant "odd" numbers. Then we gate
n/2 (2*11+(n-1)*2) = 551
Then n=19
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