Asked by Paige
You have a 2.0 M solution of HNO3. To what volume in mL would you dilute 500.0 mL to achieve a pH of 4.00?
Answers
Answered by
DrBob222
pH = 4.00 = (H^+) = 1E-4
M1V1 = M2V2
2.0M x 500 mL = 1E-4 x ?mL
M1V1 = M2V2
2.0M x 500 mL = 1E-4 x ?mL
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