Question
A 0.500 M HNO3 solution was used to titrate a 21.15 mL KOH solution. The endpoint was reached after 22.30 mL of titrant were delivered. Find the molar concentration of KOH in the original solution.
Answers
To solve for the molar concentration of KOH in the original solution, we can use the neutralization equation and the formula for moles and molar concentration.
Neutralization Equation:
HNO3 + KOH → KNO3 + H2O
Moles of HNO3 in titration = Moles of KOH in the original solution
(0.500 mol/L HNO3) * (0.0223 L HNO3) = moles of KOH
0.01115 mol = moles of KOH
Now we can find the molar concentration of KOH using its moles and the volume of the original solution (21.15 mL):
Molarity of KOH = moles of KOH / volume of KOH solution in L
Molarity of KOH = 0.01115 mol / 0.02115 L = 0.527 mol/L
So the molar concentration of KOH in the original solution is 0.527 mol/L.
Neutralization Equation:
HNO3 + KOH → KNO3 + H2O
Moles of HNO3 in titration = Moles of KOH in the original solution
(0.500 mol/L HNO3) * (0.0223 L HNO3) = moles of KOH
0.01115 mol = moles of KOH
Now we can find the molar concentration of KOH using its moles and the volume of the original solution (21.15 mL):
Molarity of KOH = moles of KOH / volume of KOH solution in L
Molarity of KOH = 0.01115 mol / 0.02115 L = 0.527 mol/L
So the molar concentration of KOH in the original solution is 0.527 mol/L.
Related Questions
An HNO3 solution has a pH of 3.04. What volume of 0.015 M LiOH will be required to titrate 89.0 mL o...
A 0.250 M NaOH solution was used to titrate a 19.75 mL HI solution. The endpoint was reached after 3...
In a titration experiment, 15.0 mL of 0.10 M Ba(OH)2 is required to titrate a 10.0 mL of an unknown...
A 0.200 M NaOH solution was used to titrate a 18.25 mL HF solution. The endpoint was reached after 3...