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One zero of x^3 - 3x^2 - 6x + 8 = 0 is -2. What are the other zeros of the function?
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Answered by
Scott
use synthetic (or long) division to reduce to a 2nd order function
(x^3 - 3x^2 - 6x + 8) / (x + 2) = ?
(x^3 - 3x^2 - 6x + 8) / (x + 2) = ?
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