One mixture contains 6 fluid ounces of water and 10 fluid ounces of vinegar. A second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar. Are the mixtures proportional? If not, how much water or vinegar would u add to the second mixture so that they are proportional?

Answer 1

6/10 ≠ 9/12
Now, do you add water or vinegar? Since

6/10 < 9/12
you must add vinegar, so its ratio diminishes. So, you must solve

9/(12+x) = 6/10
x=3

check: 9/15 = 3/5 = 6/10