Can someone help me solve this problem? This example problem will help me solve the actual homework problems
If an 0.6kg apple is dropped from 0.5m height onto a seesaw and flips up a 0.25kg kiwi. To what height does that kiwi reach. Assume all the energy of the apple transfers perfectly to the kiwi
2 answers
PE = mgh is conserved. So since the apple's mass is .6/.25 = 2.4 times the kiwi's, the kiwi rises to 2.4 times the apple's height.
the apple's energy is ... m g h
Ma * g * Ha = Mk * g * Hk
Ma / Mk = Hk / Ha
the height is inversely proportional to the mass ... heavier things don't go as high
Ma * g * Ha = Mk * g * Hk
Ma / Mk = Hk / Ha
the height is inversely proportional to the mass ... heavier things don't go as high