Asked by Lam
Mrs lee is four times as old as her son. Her son is 36 years old younger than her. How many years ago was mrs lee seven times as old as her son
Answers
Answered by
Arora
Son's age = x
Mrs Lee's age = 4x
As per the question,
4x = x + 36
=> 3x = 36
=> x = 12
=> x = 12, 4x = 48
Now, taking the number of years required as y:
(4x - y) = 7(x - y)
=> (48 - y) = 7(12 - y)
=> 48 + 6y = 84
=> 6y = 36
=> y = 6
Hence, the given case was satisfied six years ago.
Mrs Lee's age = 4x
As per the question,
4x = x + 36
=> 3x = 36
=> x = 12
=> x = 12, 4x = 48
Now, taking the number of years required as y:
(4x - y) = 7(x - y)
=> (48 - y) = 7(12 - y)
=> 48 + 6y = 84
=> 6y = 36
=> y = 6
Hence, the given case was satisfied six years ago.
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