Asked by Rich boi
Find the area under the graph of f(x) = e-ln(x) on the interval [1, 2].
Answers
Answered by
Reiny
You do realize that
f(x) = e^(-lnx) , can be changed to
f(x) = x^-1 = 1/x
so area = ∫(1/x) dx from 1 to 2
= [lnx] from 1 to 2
= ln2 - ln1
= ln2 or appr .6931...
proof:
http://www.wolframalpha.com/input/?i=%E2%88%AB(e%5E(-lnx))+dx+from+1+to+2
f(x) = e^(-lnx) , can be changed to
f(x) = x^-1 = 1/x
so area = ∫(1/x) dx from 1 to 2
= [lnx] from 1 to 2
= ln2 - ln1
= ln2 or appr .6931...
proof:
http://www.wolframalpha.com/input/?i=%E2%88%AB(e%5E(-lnx))+dx+from+1+to+2
Answered by
Steve
huh? e^(-lnx) = 1/e^(lnx) = 1/x
You can probably handle that, right?
You can probably handle that, right?
Answered by
bob
no
Answered by
guy
shut up Steve
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