Asked by Natalie
Find the area bounded by the curves y=sin(4x) and y=0 for x between x=0 and x=3pi/8.
Answers
Answered by
Reiny
Notice the period is 2π/4 or π/2 , (90°)
so your region is 1/2 a sine curve from 0 to π/4, plus a bit of the sine below the x-axis,
so take it in two parts,
from x = 0 to π/4 then the small bit below
don't forget to take
∫sin4x dx from 0 to π/4 + ∫-sin4x from π/4 to 3π/8
so your region is 1/2 a sine curve from 0 to π/4, plus a bit of the sine below the x-axis,
so take it in two parts,
from x = 0 to π/4 then the small bit below
don't forget to take
∫sin4x dx from 0 to π/4 + ∫-sin4x from π/4 to 3π/8
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