Question

Over a time interval of 1.98 years, the velocity of a planet orbiting a distant star reverses direction, changing from +21.9 km/s to -17.2 km/s. Find (a) the total change in the planet's velocity (in m/s) and (b) its average acceleration (in m/s2) during this interval. Include the correct algebraic sign with your answers to convey the directions of the velocity and the acceleration.

Please help!!

Answer 1

The total change is going to be V(final)-V(initial), so (-17.2km/s)-(21.9km/s). The acceleration will just be that difference divided by the time interval. Just make sure you convert both speeds to m/s and the time to seconds before you do any calculations.

-Carter