Asked by Amena.S
A 20 kg sphere is at the origin. A 10 kg sphere is at (x,y) = (-30cm,0cm) and a 30 kg sphere is at (0cm,40cm). Calculate the gravitational force on the 10 kg sphere, resulting from the other two spheres.
Please help! Thanks
Please help! Thanks
Answers
Answered by
bobpursley
The 10 kg sphere has a force directed +x direction of G(20*20)/.3^1
the 10 kg sphere has a force directed upward to the right of G10*20/.5^2 (3,4,5 triangle)
so this is a vector problem. first, find the components of the second force:
secondForce=G10*20/.5^2 *((4/5)j +(3/5)i)
so in the x direction:G200/.25*4/5+G200/.3^2
in the y direction: G200/.5^2 * 3/5
do determine those.
net force=sqrt(Fx^2 + Fy^2)
a bit of algebra will be needed.
the 10 kg sphere has a force directed upward to the right of G10*20/.5^2 (3,4,5 triangle)
so this is a vector problem. first, find the components of the second force:
secondForce=G10*20/.5^2 *((4/5)j +(3/5)i)
so in the x direction:G200/.25*4/5+G200/.3^2
in the y direction: G200/.5^2 * 3/5
do determine those.
net force=sqrt(Fx^2 + Fy^2)
a bit of algebra will be needed.