Question
A firecracker explodes into four equal pieces (see figure below). Given the magnitude and direction of the velocity for each piece and the coordinate system shown, determine the x and y velocity components for each piece of the firecracker. (Assume the following:
|v1| = 23.40 m/s,
|v2| = 8.20 m/s,
|v3| = 13.80 m/s,
|v4| = 21.00 m/s,
θ1 = 37°,
and
θ4 = 14°.)
v1
v1x=
v1y=
v2
v2x=
v2y=
v3
v3x=
v3y=
v4
v4x=
v4y=
|v1| = 23.40 m/s,
|v2| = 8.20 m/s,
|v3| = 13.80 m/s,
|v4| = 21.00 m/s,
θ1 = 37°,
and
θ4 = 14°.)
v1
v1x=
v1y=
v2
v2x=
v2y=
v3
v3x=
v3y=
v4
v4x=
v4y=
Answers
bobpursley
how are the angles measured?
the angle on coordinateI is 60 degree and on coordinateII is 30degree
V1: v1x=18.69m/s;v1y=14.08m/s
V2: v2x=0m/s; v2y=8.20m/s
V3: v3x=-13.80m/s:v3y=0m/s
V4: v4x= -5.08m/s;v4y=-20.38m/s
V2: v2x=0m/s; v2y=8.20m/s
V3: v3x=-13.80m/s:v3y=0m/s
V4: v4x= -5.08m/s;v4y=-20.38m/s
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