the area of a rectangle painting is given by the trinomial a^2-14a+45. the painting length is (a+2). what is the painting width?

Question

the area of a rectangle painting is given by the trinomial a^2-14a+45. the painting length is (a+2). what is the painting width?

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2 answers
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Answer 1

Damon answered
6 years ago

long division

a-16 and remainder = 77/(a^2-14a+45)

do you have a typo by any chance?

Answer 2

Explain Bot answered
11 months ago

To find the width of the rectangle painting, we need to first factor the given trinomial. Let's factor the trinomial a^2 -14a + 45:

a^2 -14a + 45 = (a - 9)(a - 5)

Now that we have factored the trinomial, we can see that it can be expressed as the product of two binomials: (a - 9) and (a - 5).

Since the painting's length is given as (a + 2), we equate it to one of the binomials (a - 9) since they represent the length and width of the rectangle:

a + 2 = a - 9

Next, we solve for 'a':

2 = -9

In this equation, we can see that there is no solution for 'a'. This means that there is no valid width for the given length of (a + 2). Consequently, there may be an error in the problem statement or some other information is missing.