Asked by Angel
Suppose that a drug is known to be 90% effective in treating a certain disease. What is the probability that it will be successful in treating seven to ten out of 12 patients with the disease?
Answers
Answered by
Arora
Probability of treating r number of patients successfully:
P(r) = (nCr)(p^r)(q^r)
Where n = Total number of patients = 12
p = probability of success = 0.90 (90%)
q = probability of failure = 0.10 (10%)
Take the different probabilities for r = 7,8,9,10 and add them up for the answer.
P(r) = (nCr)(p^r)(q^r)
Where n = Total number of patients = 12
p = probability of success = 0.90 (90%)
q = probability of failure = 0.10 (10%)
Take the different probabilities for r = 7,8,9,10 and add them up for the answer.
Answered by
Damon
and
nCr = n!/[(n-r)! r! ] the binomial coefficient
nCr = n!/[(n-r)! r! ] the binomial coefficient
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