Question

5.30g of pure anhydrous sodium carbonate, na2co3 was weighed and dissolved in a 250cm³ standard flask.The solution was made up to the etched mark with distilled water, calculate the number of moles of na2co3 in the solution.
Number of moles = Mass of substance / Molecular Mass

Molecular Mass = 106 g
Mass of substance = 5.3 g

=> Number of moles = 5.3/106
= 1/20
= 0.05

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