Question

How do I find the answer to this??

Cu metal displaces Ag+(aq) from an aqueous solution. Which of the following is correct?

Ag is easier to oxidize than Cu
Ag is a better reducing agent than Cu
Cu2+ is a better oxidizing agent than Ag+
Ag+ is easier to reduce than Cu2+

Answer 1

so thinking, you have silver ions in solution, and they are able to grab the electrons from the copper atoms, putting the copper into solution, where it exists without that electron.

silver <b>gained electron</b>: reduced, oxidizing agent
Copper atom <b>lost electron</b>, oxidized

<b> Ag+ is easier to reduce than Cu2+</b>

Ag+ is easier to reduce than Cu2+

Answer 2

If Cu displaces Ag^+ from solution then
Cu(s) + 2Ag^+*(aq) ==> Cu^2+|(aq) + 2Ag(s))

Oxidation is the loss of electrons and is the reducing agent.
Reduction is the gain of electrons and is the oxidizing agent.

So Cu changes from zero on the left to +2 on the right.
Ag changes from +1(for each) on the left to zero on the right.

Can you go from there?