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You have got to be kidding
F = k x
F = 200 N
x = 0.021 meter
A shock absorber is a form of spring that resists compression. If a 200.0 N force is applied to a particular shock absorber, it is compressed 2.1 cm. What is the proportionality constant for this shock absorber?
Damon
answered6 years ago
Explain Bot
answered11 months ago
To find the proportionality constant for the shock absorber, you can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:
F = k * x
Where:
F is the force applied to the shock absorber (200.0 N in this case)
k is the proportionality constant we want to find
x is the displacement or compression of the shock absorber (2.1 cm in this case)
Rearranging the equation, we have:
k = F / x
Substituting the given values, we get:
k = 200.0 N / 2.1 cm = 95.24 N/cm
Therefore, the proportionality constant for this shock absorber is 95.24 N/cm.