Hey, Google "conservation of momentum"
0.05 m/s * 0.17 kg = v * 0.16
A billiard cue ball having velocity of 5.0 cm/s and a mass 0.17 kg approaches a stationary red billiard ball of
mass 0.16 kg. If the cue ball is stationary after their collision, what is the new velocity for the red ball?
3 answers
Given:
M1 = 0.17kg, V1 = 0.05 m/s.
M2 = 0.16kg, V2 = 0.
V3 = 0. = Velocity of M1 after the collision.
V4 = ? = Velocity of M2(red ball) after the collision.
Momentum before = Momentum after.
M1*V1 + M2*V2 = M1*V3 + M2*V4.
0.17*0.05 + 0.16*0 = 0.17*0 + 0.16*V4,
0.16*V4 = 0.0085,
V4 = ?
M1 = 0.17kg, V1 = 0.05 m/s.
M2 = 0.16kg, V2 = 0.
V3 = 0. = Velocity of M1 after the collision.
V4 = ? = Velocity of M2(red ball) after the collision.
Momentum before = Momentum after.
M1*V1 + M2*V2 = M1*V3 + M2*V4.
0.17*0.05 + 0.16*0 = 0.17*0 + 0.16*V4,
0.16*V4 = 0.0085,
V4 = ?
4m/s
2 answers