Asked by Anonymous

How many real solutions does the function shown on the graph have?

a) no real solutions
b) one real solution
c) two real solutions
d) cannot be determined
___________________________
y = (x+2)^2 + 3 is shown on the graph.

I am having trouble figuring this one out. I have been looking in my book for a while now. Somebody please help, it would be very much appreciated!

Answers

Answered by Anonymous
I think it could be a) no real solutions?
Am I correct? If not, please explain...
Answered by Anonymous
Whoops. I meant the graph was showing: y=(x+2)^2+2
Answered by Anonymous
I was thinking that it is a) because it does not have any x-intercepts?
Answered by Bosnian
( x + 2 )² + 2 = 0

Subtract 2 to both sides

( x + 2 )² + 2 - 2 = 0 - 2

( x + 2 )²= - 2

Take square root of both sides

x + 2 = ± √( - 2 )

x + 2 = ± √( - 1 ∙ 2 )

x + 2 = ±√( - 1 ) ∙ √2

x + 2 = ± i √2

Subtract 2 to both sides

x + 2 - 2 = ± i √2 - 2

x = - 2 ± i √2

The solutions are:

x = - 2 + i √2 and x = - 2 - i √2

The function ( x + 2 )² + 2 no real solutions.

Answer a) is correct





Answered by Reiny
Just looking at the equation, we can tell that the vertex is (-2,2) and the parabola opens upwards. So clearly, it cannot cross the x-axis. So clearly, no real solution
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions