Find the 4th term from the end of the AP -11, -8, -5, .........., 49.

Answer 1

Common difference = d = a2 - a1 = -8 - (-11) = 3

If 49 is the nth term,
a(n) = a1 + (n-1)d
=> 49 = -11 + (n-1)3
=> 60 = 3n - 3
=> n = 21

So, 4th term from the end is the 18th term

a(18) = a1 + (18-1)d
= -11 + 17(3)
= -11 + 51
= 40

Answer 2

once you know d=3, just subtract it 3 times from 49:

49-3*3 = 40

Answer 3

Kaint explain kitta smj aa geya kaint, att , , ,bamb sira bhut 😍😍👌👌👌👌👌👌👌👏👏👏👏👏👏👏👏👏👏👏👏👏👌👌 thanks tanu Sharma