Asked by Anonymous
Log(base(x))x^(m-1) +1=m
I don't know how I'm supposed to prove this
I don't know how I'm supposed to prove this
Answers
Answered by
Reiny
log<sub> x </sub> x^(m-1) + 1 = m
LS = log<sub> x </sub> x^(m-1) + 1
= (m-1)log<sub> x </sub> x + 1 , (using the rule log a^n = nloga)
= (m-1)(1) + 1 , since log<sub> n </sub> n = 1
= m-1 + 1
= m
= RS
LS = log<sub> x </sub> x^(m-1) + 1
= (m-1)log<sub> x </sub> x + 1 , (using the rule log a^n = nloga)
= (m-1)(1) + 1 , since log<sub> n </sub> n = 1
= m-1 + 1
= m
= RS
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