Asked by Douchan
What is the pOH of 2.26 M Ba(OH)2?
Ba(OH)2 ==> Ba^+2 + 2OH^-
(OH)^- = 2 x 2.26 M.
pOH = - log(OH^-) = ??
Ba(OH)2 ==> Ba^+2 + 2OH^-
(OH)^- = 2 x 2.26 M.
pOH = - log(OH^-) = ??
Answers
Answered by
asmain
yes
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