Asked by meh
What is the graph of the system?
y ≤ −x − 1
y ≥ 2x + 4
Would I use elimination for this?
y ≤ −x − 1
y ≥ 2x + 4
Would I use elimination for this?
Answers
Answered by
Steve
the solution is not just a point, which you could get by using elimination.
y <= x-1 is the whole half-plane, below the line y = x-1
y >= 2x+4 is the whole half-plane above the line y = 2x-4
So, graph those two lines and shade in the area which is below the first line and above the second line:
http://www.wolframalpha.com/input/?i=solve+y+%E2%89%A4+%E2%88%92x+%E2%88%92+1,+y+%E2%89%A5+2x+%2B+4
Include the lines (draw them as solid lines) because the inequalities both include "equal to." If they had been
y < −x − 1
y > 2x + 4
then you'd draw dashed lines to indicate that the boundaries are not to be included.
y <= x-1 is the whole half-plane, below the line y = x-1
y >= 2x+4 is the whole half-plane above the line y = 2x-4
So, graph those two lines and shade in the area which is below the first line and above the second line:
http://www.wolframalpha.com/input/?i=solve+y+%E2%89%A4+%E2%88%92x+%E2%88%92+1,+y+%E2%89%A5+2x+%2B+4
Include the lines (draw them as solid lines) because the inequalities both include "equal to." If they had been
y < −x − 1
y > 2x + 4
then you'd draw dashed lines to indicate that the boundaries are not to be included.
Answered by
meh
Thanks for the help
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