Asked by Albert

A skier wants to build a rope tow to pull herself up a ski hill that is inclined at 15 with the horizontal. Calculate the tension needed in the rope to give the skier's 54kg body a 1.2 m/s^2 acceleration.
Answered by bobpursley
see other post.
Answered by Henry
M*g = 54 * 9.8 = 529.2 N. = Wt. of skier.

Fp = 529.2*sin15 = 137 N. = Force parallel to the hill.

Fn = 529.2*Cos15 = 511 N. = Normal force.

Fap-Fp = M*a.
Fap-137 = 54*1.2,
Fap = 201.8 N. = Applied force = Tension in rope.
Answered by rovic
tuleg
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