A room 5 M long and 4 m wide is surrounded by a wonder if the verandah occupies an area of 22 metre square find the width of the verandah

Answer 1

The figure can be imagined as a smaller rectangle (the room) inside a larger rectangle (room plus verandah).

Area of veranda = Area of outer rectangle - Area of room

If you draw the figure, you'll see:
Length of outer rec. = (5+2x)
Width of outer rec. = (4+2x)
Length of room = 5
Width of room = 4
Where, x = width of the verandah

Area of veranda = Area of outer rectangle - Area of room
=> 22 = (5+2x)(4+2x) - 5*4
=> 22 = 8x + 10x + 4x^2
=> 2x^2 + 9x - 11 = 0
=> (2x+11)(x-1) = 0
=> x = 1, x = -11/2

Since the width cannot be negative, x = 1 meter

Answer 2

length = 5 + 2 w
width = 4 + 2 w

area = 22 = (2w+5)(2w+4) - 20
solve quadratic for w
22 = 4w^2 + 18w + 20 - 20
4 w^2 + 18 w - 22 = 0
2 w^2 + 9 w - 11 = 0
(2w+11)(w-1) = 0
w = 1

Answer 3

let width be x

length=5+x+x=5+2x
Width =4+x+x=4+2x

area=42m^2

so, (5+2x)x(4+2x)=42
(5x4)+(2x*2x)=42
2x*2x=42-(5x4)
2x*2x=22
x*x=22/(2x2)
x^2=5.5
x=5.5-3.5
x=1

THANK YOU !!!!!!!!!!!!!!!!!!..............

Answer 4

IS THIS REALLY THE CORRECT ANSWER???

Answer 5

IS THIS REALLY THE CORRECT ANSWER??? AND WHAT IS ^ THIS HERE ???

Answer 6

Width so you have to substitute X=1 into 4+2(1)=6
Therefore, the width of the verandah is 6m