Asked by c
                a metal p forms 2 different chlorides x and y. if 12.7g of chloride x and 16.3g of chloride y contain 7.1g 10.7g of chlorine respectively, show that the figures agree with the law of multiple proportion
            
            
        Answers
                    Answered by
            Arora
            
    Law of multiple proportions:
"When two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers"
=>12.7g of chloride X has 7.1g of Cl
=>16.3g of chloride Y has 10.7g of Cl
Hence,
10.81g of chloride Y has 7.1g of Cl
(Using the unitary method)
So, for fixed weights of Cl in both chlorides, we have:
P in X = 12.7 - 7.1 = 5.6g
P in Y = 10.81 - 7.1 = 3.7g
Ratio of P in both compunds = 5.6:3.7
Which is approx. 3:2
Hence, the figures agree with the law of multiple proportions.
    
"When two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers"
=>12.7g of chloride X has 7.1g of Cl
=>16.3g of chloride Y has 10.7g of Cl
Hence,
10.81g of chloride Y has 7.1g of Cl
(Using the unitary method)
So, for fixed weights of Cl in both chlorides, we have:
P in X = 12.7 - 7.1 = 5.6g
P in Y = 10.81 - 7.1 = 3.7g
Ratio of P in both compunds = 5.6:3.7
Which is approx. 3:2
Hence, the figures agree with the law of multiple proportions.
                    Answered by
            Dominion
            
    Very good
    
                    Answered by
            Tola
            
    Iron combines with chlorine to form two chloride. If 12.7g of chloride X and 16.3g of chloride Y contain 7.1g and 10.7g of chlorine respectively show that figure agree with law of multiple proportion 
    
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