Question

A 2.55-g piece of stainless steel absorbs 131J of heat when its temperature increases by 152°C. What is the specific heat of the stainless steel?

How do I do this???

Answer 1

heat in = C m (T2-T1)
find Sheat

131 in Joules = Sheat (in Joules/kg deg K) *(.00255 kg)*(152 deg K)
so
Sheat = 131 / (.00255*152) J/kg deg K

change in degrees K is the same as change in degrees C (K = C+273)

Answer 2

thanks

Answer 3

You are welcome.