Question

A bead slides without friction around a loopthe-loop.
The bead is released from a height
of 18.6 m from the bottom of the loop-theloop
which has a radius 7 m.
The acceleration of gravity is 9.8 m/s
2
.
18.6 m
7 m
A
What is its speed at point A ?
Answer in units of m/s.

Answer 1

I do not know where point A is
however if it is at height h
then
mg(18.6) - mg(h) = (1/2) m v^2
so
v = sqrt [ 2 * 9.8 * (18.6-h) ]