Asked by Dillon

A 21kg crate is pushed across the floor at a constant velocity by a 350N force. Determine the coefficient of kinetic friction.
Answered by bobpursley
350=mu*21*9.8
solve for mu
Answered by Henry
M*g = 21 * 9.8 = 205.8 N. = Wt. of crate = Normal force(Fn).

Fk = u*Fn = 205.8u.

Fap-Fk = M*a.
350-205.8u = 21*0,
u = ?.

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