1) close, you left out the derivative of the base, so
dy/dx = - 1/ 3(sinx) ^4/3(cosx)
for 2)
rewrite it as
y = (8+sin(6x))^1/2
dy/dx = (1/2)((8+sin(6x))^-1/2)(cos(6x))(6)
= 3cos(6x)((8+sin(6x))^-1/2)
Need help to find dy/dx:
1) y = (sin x) ^-1/3
answer dy/dx = - 1/ 3(sinx) ^4/3
2) y = sqrt 8 + sin(6x)
answer - lost
1 answer