find the number of radians in the central angle that subtends an arc of 6m on a circle of diameter 5m

User Icon for cylinder cylinder answered
6 years ago

θ = s/r = (6 m)/(5/2 m) = 12/5 radians = 2.4 radians



r = s/θ = (60 ft)/(3π/2) = 40/π ft ≅ 12.732 ft

User Icon for Bella Bella answered
3 years ago

θ = s/r = (6 m)/(5/2 m)

(6/1)(2/5)= 12/5 (2.4)
= 2.4 radians

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the number of radians in the central angle that subtends an arc of 6m on a circle of diameter 5m, we can use the formula:

Arc Length = Radius × Central Angle

Given that the diameter is 5m, the radius is half of the diameter, which is 2.5m. The arc length is given as 6m.

Plugging these values into the formula:

6m = 2.5m × Central Angle

Simplifying the equation:

Central Angle = 6m / 2.5m

Central Angle = 2.4 radians

Therefore, the number of radians in the central angle that subtends an arc of 6m on a circle of diameter 5m is approximately 2.4 radians.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the number of radians in a central angle that subtends an arc, you need to use the formula:

radians = arc length / radius

In this case, the arc length is given as 6m, and the radius is half of the diameter, which is 5m/2 = 2.5m.

Substituting these values into the formula, we get:

radians = 6m / 2.5m = 2.4 radians

Therefore, the central angle that subtends an arc of 6m on a circle of diameter 5m is 2.4 radians.