Asked by jay
sin(pi/2+x)cos(pi-x)cot(3pi/+x)=sin(pi/2-x)sin(3pi/2-x)cot(pi/2+x
Answers
Answered by
Steve
use your sum/formulas. For example,
sin(pi/2+x) = cosx
cos(pi-x) = -cosx
and so on. Then the products will be much easier to manipulate.
sin(pi/2+x) = cosx
cos(pi-x) = -cosx
and so on. Then the products will be much easier to manipulate.
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