1.00 g Li ... plus ... 2.73 g F
divide by their respective molar masses to find the molar ratio of the empirical formula
Hello I understand How to do empirical problems, but the way this problem is worded has me so confused.
when 1.00g lithium metal is reacted with fluorine gas, the RESULTING COMPOUND has a mass of 3.73g. Calc the emprical fromula of lithium fluoride.
I know for lithium i would 1.00g/its molar mass
I am confused what would be fluorine would it be 99g? or 2.73? Please help me
2 answers
Remember the Law of Conservation of Mass. What you start with on the left must equal what you end uyp with on the right.
2Li + F2 ==> 2LiF
1.00. +x = 3.73 so what's x?
2Li + F2 ==> 2LiF
1.00. +x = 3.73 so what's x?