Asked by Anon

The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.
a(t) = 2t + 2,    v(0) = −3,    0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m

Thank you!

Answers

Answered by Steve
v(t) = ∫a(t) dt = ∫(2t+2) dt = t^2+2t+C
v(0) = -3, so C = -3
v(t) = t^2+2t-3

s(t) = ∫[0,5] v(t) dt = ...
Answered by Anon
The first part was correct and I got 155/3 m for B however, my homework system won't take that answer and doesn't want it as a decimal either. That is the answer, correct?
Answered by Damon
NO - I did this last night

The thing moves backwards from zero
then forward again

You found the displacement, not the distance.
Answered by Damon
https://www.jiskha.com/display.cgi?id=1512879704
Answered by Steve
That was my bad, but he should have read and analyzed your solution.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions