Asked by Anon
                The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.
a(t) = 2t + 2, v(0) = −3, 0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m
Thank you!
            
        a(t) = 2t + 2, v(0) = −3, 0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m
Thank you!
Answers
                    Answered by
            Steve
            
    v(t) = ∫a(t) dt = ∫(2t+2) dt = t^2+2t+C
v(0) = -3, so C = -3
v(t) = t^2+2t-3
s(t) = ∫[0,5] v(t) dt = ...
    
v(0) = -3, so C = -3
v(t) = t^2+2t-3
s(t) = ∫[0,5] v(t) dt = ...
                    Answered by
            Anon
            
    The first part was correct and I got 155/3 m for B however, my homework system won't take that answer and doesn't want it as a decimal either. That is the answer, correct?
    
                    Answered by
            Damon
            
    NO - I did  this last night
The thing moves backwards from zero
then forward again
You found the displacement, not the distance.
    
The thing moves backwards from zero
then forward again
You found the displacement, not the distance.
                    Answered by
            Damon
            
    https://www.jiskha.com/display.cgi?id=1512879704
    
                    Answered by
            Steve
            
    That was my bad, but he should have read and analyzed your solution.
    
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