Asked by Anon
The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.
a(t) = 2t + 2, v(0) = −3, 0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m
Thank you!
a(t) = 2t + 2, v(0) = −3, 0 ≤ t ≤ 5
(a) Find the velocity at time t.
v(t) = ______ m/s
(b) Find the distance traveled during the given time interval.
_____ m
Thank you!
Answers
Answered by
Steve
v(t) = ∫a(t) dt = ∫(2t+2) dt = t^2+2t+C
v(0) = -3, so C = -3
v(t) = t^2+2t-3
s(t) = ∫[0,5] v(t) dt = ...
v(0) = -3, so C = -3
v(t) = t^2+2t-3
s(t) = ∫[0,5] v(t) dt = ...
Answered by
Anon
The first part was correct and I got 155/3 m for B however, my homework system won't take that answer and doesn't want it as a decimal either. That is the answer, correct?
Answered by
Damon
NO - I did this last night
The thing moves backwards from zero
then forward again
You found the displacement, not the distance.
The thing moves backwards from zero
then forward again
You found the displacement, not the distance.
Answered by
Damon
https://www.jiskha.com/display.cgi?id=1512879704
Answered by
Steve
That was my bad, but he should have read and analyzed your solution.