Asked by y912f
find the exact values of s in the given intervals that have the given circular function values.
1. [pi/2,pi]; sin s=square root 2/2
2. [pi/2,pi]; cos s=-square root 3/2
1. [pi/2,pi]; sin s=square root 2/2
2. [pi/2,pi]; cos s=-square root 3/2
Answers
Answered by
Damon
these are simple angles
sin 45 degrees = (sqrt 2) /2
cos 30 deg = (sqrt 3)/2
But
Look, you need a calculator. Here is one.
For example for the angle whose sin is .75
type asin(.75) and click on the equal sign.
http://www.mathsisfun.com/scientific-calculator.html
sin 45 degrees = (sqrt 2) /2
cos 30 deg = (sqrt 3)/2
But
Look, you need a calculator. Here is one.
For example for the angle whose sin is .75
type asin(.75) and click on the equal sign.
http://www.mathsisfun.com/scientific-calculator.html
Answered by
Damon
Oh, did not notice between 90 and 180 degrees
180 - 45 = 135 degrees
180 - 30 = 150 degrees
180 - 45 = 135 degrees
180 - 30 = 150 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.