1. What is the maximum volume (at STP) of the butene mixture that could be obtained by the dehydration of 81 mg of 2-butanol?
2. When 2-methylpropene is bubbled into dilute sulfuric acid at room temperature, it appears to dissolve. What new substance has been formed?
Responses
* O Chem - DrBob222, Monday, January 5, 2009 at 8:52pm
" 1. Write the equation for the dehydration of 2-butanol and balance it. You need not worry about where the double bond goes, just the empirical formula is all you need.
2. mols = 0.081g/molar mass 2-butanol.
3. Using the coefficients in the balanced equation, (I think it will be 1:1), convert mols 2-butanol to the product.
4. Convert mols to liters remembering that 1 mol occupies 22.4 L at STP. I note the problem talks about a "mixture of products" but you can only work this problem for ONE product unless you know the percentages of the various products.
For 2. I suspect that you will hydrate the double bond. Look in your book to find if this follows the Markovnikov's rule or not. "
---------------------------------
For 1 is it just 81 mg/ (74.12 g/mol x 100) = 1.09 mol x 22.4 L= -->0.024L ???
For 2 is it just gunna be 2-methylpropane instead of propene because the double bond is taken off?