Calculate the work in kilojoules done during a reaction in which the volume expands from 10.0 L to 95.9 L against an external pressure of 2.5 atm.

Answer 1

what is Pressure*volume?
85.9*2.5*101kPa*dm^3== 21689750e-6 Pa*L^3

but what is a Pa? force/m^2=N/m^2
so Pa*m^3=Joules
PV=21.7Joules