Question
The Ka of HClO is 3.0x 10^-8 at 25°c. What is the percent ionization of HClO in a 0.015M aqueous solution of HCLO at 25°c?
Answers
DrBob222
............HClO ==> H^+ + ClO^-
I..........0.015.....0......0
C...........-x.......x......x
E.........0.015-x....x......x
Ka = (H^+)(ClO^-)/(HClO)
Plug in the E line into Ka expession, solve for x, then %ionization = [(x)/0.015]*100 = ?
I..........0.015.....0......0
C...........-x.......x......x
E.........0.015-x....x......x
Ka = (H^+)(ClO^-)/(HClO)
Plug in the E line into Ka expession, solve for x, then %ionization = [(x)/0.015]*100 = ?
joe
0.14
joe
percent ionization=concentration of ionized acid/initial concentration of acid*100
[H3O+]equil/HA]init*100%
[H3O+]equil/HA]init*100%