Asked by Zekariyas
The Ka of HClO is 3.0x 10^-8 at 25°c. What is the percent ionization of HClO in a 0.015M aqueous solution of HCLO at 25°c?
Answers
Answered by
DrBob222
............HClO ==> H^+ + ClO^-
I..........0.015.....0......0
C...........-x.......x......x
E.........0.015-x....x......x
Ka = (H^+)(ClO^-)/(HClO)
Plug in the E line into Ka expession, solve for x, then %ionization = [(x)/0.015]*100 = ?
I..........0.015.....0......0
C...........-x.......x......x
E.........0.015-x....x......x
Ka = (H^+)(ClO^-)/(HClO)
Plug in the E line into Ka expession, solve for x, then %ionization = [(x)/0.015]*100 = ?
Answered by
joe
0.14
Answered by
joe
percent ionization=concentration of ionized acid/initial concentration of acid*100
[H3O+]equil/HA]init*100%
[H3O+]equil/HA]init*100%
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.